¿6(4-2x)-(2(x+3)<=5(2-4x)+6?

6 (4 - 2x) - 2 (x + 3) ≤ 5 (2 - 4x) + 6

24 - 12x - 2x - 6 ≤ 10 - 20x + 6

-14x + 18 ≤ -20x + 16

6x ≤ -2

x ≤ -2/6

x ≤ -1/3

o

6(4-2x)-(2(x+3))<=5(2-4x)+6

3(4-2x) - (x+3) <= 5(1-2x) + 3

12 - 6x - x - 3 <= 5 - 10x + 3

10x - 6x - x <= 5 + 3 + 3 - 12

3x <= -1

x <= -1/3 y WALA !!

-∞ ... -5 ... -4 ... -3 ... -2 ... -1 .... -2/3 ... -1/3 ... 0

<==============================I

........ ........... x<= -1/3 

intervalo abierto x ε (-∞, -1/3]

•24-12x-2x-6≤10-20x+6.

•18-14x≤16-20x.

•18-16≤14x-20x.

•2≤-6x.

•(-2)≥6x.

•(-2/6)≥x.

•x≤(-1/3).

•Solución:

•x≤(-1/3).

•Para todos los x€R / x€{(-♾️,-1/3]}.

OKJJJJJJJJJJJJJ

  6(4-2x)-2(x+3)≤5(2-4x)+6

     18-14x≤16-20x

    20x-14x≤16-18

     6x≤-2

    ((6x)/6)≤-(2/6)

     x≤-(1/3)

    (-∞,-(1/3)]

    6(4-2x)-2(x+3)≤5(2-4x)+6

     18-14x≤16-20x

    20x-14x≤16-18

     6x≤-2

    ((6x)/6)≤-(2/6)

     x≤-(1/3)

    (-∞,-(1/3)]

24 - 12x - 2x - 6 = 10 - 20x + 6

18 - 16 = - 20x + 14x

2 = - 6x

x = - 2/6 = - 1/3